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games above .500 · final standings
1939 MLB AL standings
The New York Yankees won the 1939 American League pennant race at 106-45, 17 games ahead of the Boston Red Sox.
🏆How the 1939 playoffs went
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AL standings, 1939
| Team | W | L | Pct | GB | L10 | Streak |
|---|
| New York Yankees (NYY) | 106 | 45 | .702 | - | 8-2 | L1 |
| Boston Red Sox (BOS) | 89 | 62 | .589 | 17 | 7-3 | W1 |
| Cleveland Indians (CLE) | 87 | 67 | .565 | 20.5 | 6-4 | L1 |
| Chicago White Sox (CWS) | 85 | 69 | .552 | 22.5 | 6-4 | L1 |
| Detroit Tigers (DET) | 81 | 73 | .526 | 26.5 | 7-3 | W1 |
| Washington Senators (WAS) | 65 | 87 | .428 | 41.5 | 4-6 | W2 |
| Philadelphia Athletics (PHA) | 55 | 97 | .362 | 51.5 | 3-7 | L1 |
| St. Louis Browns (SLB) | 43 | 111 | .279 | 64.5 | 2-8 | W1 |
Final standings.
Turning points
- The lead changed hands 8 times.
- The New York Yankees trailed by as many as half a game on April 18, 1939.
- The New York Yankees took first place for good on May 11, 1939.
- The New York Yankees won 12 games in a row from May 9, 1939 to May 23, 1939, the longest run of the race.
- The New York Yankees went 31-6 from May 6, 1939 to June 17, 1939, turning a deficit of half a game into a lead of 12 games.
- Eight teams held first place.
- The New York Yankees spent 159 of the season's 168 charted days in first place.