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games above .500 · final standings
1918 MLB AL standings
The Boston Red Sox won the 1918 American League pennant race at 75-51, 2.5 games ahead of the Cleveland Indians.
🏆How the 1918 playoffs went
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AL standings, 1918
| Team | W | L | Pct | GB | L10 | Streak |
|---|
| Boston Red Sox (BOS) | 75 | 51 | .595 | - | 6-4 | L1 |
| Cleveland Indians (CLE) | 73 | 54 | .575 | 2.5 | 7-3 | W4 |
| Washington Senators (WAS) | 72 | 56 | .563 | 4 | 8-2 | W1 |
| New York Yankees (NYY) | 60 | 63 | .488 | 13.5 | 4-6 | W1 |
| St. Louis Browns (SLB) | 58 | 64 | .475 | 15 | 5-5 | W1 |
| Chicago White Sox (CWS) | 57 | 67 | .460 | 17 | 2-8 | L8 |
| Detroit Tigers (DET) | 55 | 71 | .437 | 20 | 5-5 | W2 |
| Philadelphia Athletics (PHA) | 52 | 76 | .406 | 24 | 4-6 | L1 |
Final standings.
Turning points
- The lead changed hands 9 times.
- The Boston Red Sox trailed by as many as 1 game on June 28, 1918.
- The Boston Red Sox took first place for good on July 6, 1918.
- The New York Yankees led by 1 game as late as June 28, 1918.
- The Boston Red Sox went 15-3 from July 4, 1918 to July 22, 1918, turning a deficit of 1 game into a lead of 6.5 games.
- The top two ended the day within one game of each other on 32 of the 139 days played.
- Three teams held first place.
- The Boston Red Sox spent 129 of the season's 141 charted days in first place.